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Question: PHP fopen path is not working [duplicate]


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Question author User2107349 | Source



You have forgot to add semicolon (;).


$path = "/print/"
@ $fp = fopen("$path""$filename", "wb");

To this

$path = "/print/";
@ $fp = fopen("$path" . "$filename", "wb");
Answer author Vasil-shaddix

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